Date ______________
Period ____________
So(diamond) = 0.58 cal/mole
So (graphite) = 1.37 cal/mole
Hof CO2 (graphite) = - 94.48 kilocalories/mol
Hof CO2 (diamond) = - 94.03 kilocalories/mol
Consider the change: C(graphite) = C(diamond) at 298 K and 1 atmosphere.
a. What are the values of ∆So and ∆Ho for the conversion of graphite to diamond.
b. Perform a calculation to show whether it is thermodynamically feasible to produce diamond from graphite at 298 K and 1 atmosphere.
b. From each of the following pairs of substances, choose the one expected to have the greater absolute entropy. Explain your choice in each case. Assume 1 mole of each substance.
1. He(g) at 1 atmosphere and He(g) at 0.05 atmosphere, both at the same temperature.
2. H2O(l) or CH3CH2OH(l) at the same temperature and pressure.
3. Mg(s) at 0oC or Mg(s) at 150oC, both at the same pressure.
E.C. Pb(s) or C(graphite) at the same temperature and pressure. (hint: compare bonding types)
For the reaction above, ∆Ho = +22.1 kilocalories per mole at 25oC
4.
|
Substance |
Enthalpy of Combustion (kJ/mol) |
Absolute Entropy (J/mol K) |
|
C(s, graphite) |
- 393.5 |
5.740 |
|
H2(g) |
- 285.8 |
130.6 |
|
C2H5OH(l) |
- 1366.7 |
160.7 |
|
H2O(l) |
- |
69.91 |
a. Write a separate, balanced chemical equation for the combustion of each of the following: C(s), H2(g), and C2H5OH(l). Consider the only products to be CO2 and/or H2O(l)
b. In principle, ethanol can be prepared by the following reaction:
2 C(s) + 2 H2(g) + H2O(l) à C2H5OH(l)
Calculate the standard enthalpy change for the preparation of ethanol,
as shown in the reaction above.
c. Calculate the standard entropy change for the reaction given in part b.
d. Calculate the value of the equilibrium constant at 25oC for the reaction represented by the equation in part b.